10x^2=25+15x

Solution for 10x^2=25+15x equation:

10x^2=25+15x

We move all terms to the left:

10x^2-(25+15x)=0

We add all the numbers together, and all the variables

10x^2-(15x+25)=0

We get rid of parentheses

10x^2-15x-25=0

a = 10; b = -15; c = -25;
Δ = b2-4ac
Δ = -152-4·10·(-25)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-35}{2*10}=\frac{-20}{20}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+35}{2*10}=\frac{50}{20}
=2+1/2
$